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(An embedded mixed-sign quadric family) Let $n\geq 3$, $n/2<k<n$, and $S=2k-n>0$. Put
The domain is the mapping torus
This exact map gives a complete proper embedded Lagrangian of dimension and codimension $n$ in $\mathbb C^ n$, with $\vec H=-X^\perp /2$. Its flow is $L_ t=\sqrt{-t}\, X(Q_+\times \mathbb R)$ for $t<0$. These are the unit-weight cases of [LeeWang2010], Propositions 2.1–2.2: the weights are $k$ copies of $1$ and $n-k$ copies of $-1$.
The fiber $Q_+$ is $S^{k-1}\times \mathbb R^{n-k}$. The antipodal gluing is part of the topology; a product with $S^1$ cannot in general replace this mapping torus. The full manifold is connected, noncompact, and has one end. When $n-k=1$ the gluing exchanges the two fiber ends; otherwise the fiber already has one end. It is orientable exactly when $n$ is even. The $n=3$, $k=2$ case is a nonorientable three-manifold, not a surface with a genus.
The $SO(k)\times SO(n-k)$ action and the indicated circle action preserve the image. The Lagrangian angle is $Ss+\pi /2$ locally; it is harmonic, so the example is Hamiltonian stationary, although it is not stationary under MCF. It is asymptotic to the corresponding quadric cone. Properness follows directly from $|X|=|x|$ on the mapping torus. Its polynomial volume growth gives finite entropy, equal to centered Gaussian area in this normalized shrinker setting; no numerical value or stability theorem is asserted here. The figure uses the exact $n=3$, $k=2$ case, as explained below. The companion expander is Example 4.18.
For the illustrated weights $(1,1,-1)$, put $r_ t(u)=\sqrt{u^2-2t}$. At $t<0$ the complete flow has the explicit coordinates
The circle coordinate obeys $(\theta ,u,s+\pi )\sim (\theta +\pi ,-u,s)$. Fixing $s=0$ gives $x_1^2+x_2^2-x_3^2=-2t$ and waist radius $\sqrt{-2t}$. The four views use one spatial scale and the fixed ambient crop $|F_ t|\leq 3.6$. Thus the shrinking waist approaches the cone while the noncompact ends remain visible. The cut edges are display boundaries. The phase leaves are two-dimensional slices of the full flow, and are not themselves surface mean curvature flows in $\mathbb R^3$.
The circle-action view projects a selected phase leaf and sampled circle orbits by
Changing $s$ changes a spatial coordinate, not the time. Crossings in this projection need not be self-intersections in $\mathbb R^6$. The optional positive-time views use the same quadric equation, with $x_3=\pm \sqrt{x_1^2+x_2^2+2t}$. These two real sheets belong to the connected companion expander after circle gluing. The $t=0$ cone is singular; Theorem 1.1 and Section 3 of [LeeWang2010] give the Brakke continuation through it without mass loss, rather than a smooth flow across zero.
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